Friday, August 2, 2013

php - Unexpected $end in eval()'d code [Solve]

why we geting this error :  "Unexpected $end in eval()'d code" or "Parse error: syntax error, unexpected $end" or any syntax related error
because we just execute the statement not print the statement. ok lets check the statement
if we execute the program it ll give the error because the statement ll come like this

myclass::function1() but you eval() method doing execute the php code not print the statement.

so we need to correct into eval() the PHP statement like myclass::function1(); in here ";" semicolon is missed that why the error. i think you got my point

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